JObject ci = JsonConvert.DeserializeObject<JObject>(row);
string s = ci["txtContent"].ToString();本文共 148 字，大约阅读时间需要 1 分钟。
JObject ci = JsonConvert.DeserializeObject<JObject>(row);
string s = ci["txtContent"].ToString();转载于:https://www.cnblogs.com/balcon/p/10637384.html